+};
+
+// Time granularity enumeration
+Dygraph.SECONDLY = 0;
+Dygraph.TWO_SECONDLY = 1;
+Dygraph.FIVE_SECONDLY = 2;
+Dygraph.TEN_SECONDLY = 3;
+Dygraph.THIRTY_SECONDLY = 4;
+Dygraph.MINUTELY = 5;
+Dygraph.TWO_MINUTELY = 6;
+Dygraph.FIVE_MINUTELY = 7;
+Dygraph.TEN_MINUTELY = 8;
+Dygraph.THIRTY_MINUTELY = 9;
+Dygraph.HOURLY = 10;
+Dygraph.TWO_HOURLY = 11;
+Dygraph.SIX_HOURLY = 12;
+Dygraph.DAILY = 13;
+Dygraph.WEEKLY = 14;
+Dygraph.MONTHLY = 15;
+Dygraph.QUARTERLY = 16;
+Dygraph.BIANNUAL = 17;
+Dygraph.ANNUAL = 18;
+Dygraph.DECADAL = 19;
+Dygraph.NUM_GRANULARITIES = 20;
+
+Dygraph.SHORT_SPACINGS = [];
+Dygraph.SHORT_SPACINGS[Dygraph.SECONDLY] = 1000 * 1;
+Dygraph.SHORT_SPACINGS[Dygraph.TWO_SECONDLY] = 1000 * 2;
+Dygraph.SHORT_SPACINGS[Dygraph.FIVE_SECONDLY] = 1000 * 5;
+Dygraph.SHORT_SPACINGS[Dygraph.TEN_SECONDLY] = 1000 * 10;
+Dygraph.SHORT_SPACINGS[Dygraph.THIRTY_SECONDLY] = 1000 * 30;
+Dygraph.SHORT_SPACINGS[Dygraph.MINUTELY] = 1000 * 60;
+Dygraph.SHORT_SPACINGS[Dygraph.TWO_MINUTELY] = 1000 * 60 * 2;
+Dygraph.SHORT_SPACINGS[Dygraph.FIVE_MINUTELY] = 1000 * 60 * 5;
+Dygraph.SHORT_SPACINGS[Dygraph.TEN_MINUTELY] = 1000 * 60 * 10;
+Dygraph.SHORT_SPACINGS[Dygraph.THIRTY_MINUTELY] = 1000 * 60 * 30;
+Dygraph.SHORT_SPACINGS[Dygraph.HOURLY] = 1000 * 3600;
+Dygraph.SHORT_SPACINGS[Dygraph.TWO_HOURLY] = 1000 * 3600 * 2;
+Dygraph.SHORT_SPACINGS[Dygraph.SIX_HOURLY] = 1000 * 3600 * 6;
+Dygraph.SHORT_SPACINGS[Dygraph.DAILY] = 1000 * 86400;
+Dygraph.SHORT_SPACINGS[Dygraph.WEEKLY] = 1000 * 604800;
+
+// NumXTicks()
+//
+// If we used this time granularity, how many ticks would there be?
+// This is only an approximation, but it's generally good enough.
+//
+Dygraph.prototype.NumXTicks = function(start_time, end_time, granularity) {
+ if (granularity < Dygraph.MONTHLY) {
+ // Generate one tick mark for every fixed interval of time.
+ var spacing = Dygraph.SHORT_SPACINGS[granularity];
+ return Math.floor(0.5 + 1.0 * (end_time - start_time) / spacing);
+ } else {
+ var year_mod = 1; // e.g. to only print one point every 10 years.
+ var num_months = 12;
+ if (granularity == Dygraph.QUARTERLY) num_months = 3;
+ if (granularity == Dygraph.BIANNUAL) num_months = 2;
+ if (granularity == Dygraph.ANNUAL) num_months = 1;
+ if (granularity == Dygraph.DECADAL) { num_months = 1; year_mod = 10; }
+
+ var msInYear = 365.2524 * 24 * 3600 * 1000;
+ var num_years = 1.0 * (end_time - start_time) / msInYear;
+ return Math.floor(0.5 + 1.0 * num_years * num_months / year_mod);
+ }
+};
+
+// GetXAxis()
+//
+// Construct an x-axis of nicely-formatted times on meaningful boundaries
+// (e.g. 'Jan 09' rather than 'Jan 22, 2009').
+//
+// Returns an array containing {v: millis, label: label} dictionaries.
+//
+Dygraph.prototype.GetXAxis = function(start_time, end_time, granularity) {
+ var ticks = [];
+ if (granularity < Dygraph.MONTHLY) {
+ // Generate one tick mark for every fixed interval of time.
+ var spacing = Dygraph.SHORT_SPACINGS[granularity];
+ var format = '%d%b'; // e.g. "1Jan"
+
+ // Find a time less than start_time which occurs on a "nice" time boundary
+ // for this granularity.
+ var g = spacing / 1000;
+ var d = new Date(start_time);
+ if (g <= 60) { // seconds
+ var x = d.getSeconds(); d.setSeconds(x - x % g);
+ } else {
+ d.setSeconds(0);
+ g /= 60;
+ if (g <= 60) { // minutes
+ var x = d.getMinutes(); d.setMinutes(x - x % g);
+ } else {
+ d.setMinutes(0);
+ g /= 60;
+
+ if (g <= 24) { // days
+ var x = d.getHours(); d.setHours(x - x % g);
+ } else {
+ d.setHours(0);
+ g /= 24;
+
+ if (g == 7) { // one week
+ d.setDate(d.getDate() - d.getDay());
+ }
+ }
+ }
+ }
+ start_time = d.getTime();
+
+ for (var t = start_time; t <= end_time; t += spacing) {
+ var d = new Date(t);
+ var frac = d.getHours() * 3600 + d.getMinutes() * 60 + d.getSeconds();
+ if (frac == 0 || granularity >= Dygraph.DAILY) {
+ // the extra hour covers DST problems.
+ ticks.push({ v:t, label: new Date(t + 3600*1000).strftime(format) });
+ } else {
+ ticks.push({ v:t, label: this.hmsString_(t) });
+ }
+ }
+ } else {
+ // Display a tick mark on the first of a set of months of each year.
+ // Years get a tick mark iff y % year_mod == 0. This is useful for
+ // displaying a tick mark once every 10 years, say, on long time scales.
+ var months;
+ var year_mod = 1; // e.g. to only print one point every 10 years.
+
+ if (granularity == Dygraph.MONTHLY) {
+ months = [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 ];
+ } else if (granularity == Dygraph.QUARTERLY) {
+ months = [ 0, 3, 6, 9 ];
+ } else if (granularity == Dygraph.BIANNUAL) {
+ months = [ 0, 6 ];
+ } else if (granularity == Dygraph.ANNUAL) {
+ months = [ 0 ];
+ } else if (granularity == Dygraph.DECADAL) {
+ months = [ 0 ];
+ year_mod = 10;
+ }
+
+ var start_year = new Date(start_time).getFullYear();
+ var end_year = new Date(end_time).getFullYear();
+ var zeropad = Dygraph.zeropad;
+ for (var i = start_year; i <= end_year; i++) {
+ if (i % year_mod != 0) continue;
+ for (var j = 0; j < months.length; j++) {
+ var date_str = i + "/" + zeropad(1 + months[j]) + "/01";
+ var t = Date.parse(date_str);
+ if (t < start_time || t > end_time) continue;
+ ticks.push({ v:t, label: new Date(t).strftime('%b %y') });
+ }
+ }
+ }
+
+ return ticks;
+};
+
projects / dygraphs.git / blobdiff